(Answered): The content of PC in the basic accumulator computer is 323. This machine has only one accumulator 1 ...

The content of PC in the basic accumulator computer is 323. This machine has only one accumulator 16-bit register AC. The initial content of AC is 7EC3. Part of the memory is shown in the following table: Memory Address Cell content 323 832E 324 D32F 32E 09AC 32F 0100 9AC 8B9F Alhof the above numbers are in Hexadecimal. All instructions are 16-bit instruction with the following format: Opcode 14 Memory Address (12 bits) pits) Uuue 4 Memory Address ITZ DITS bits) The opcodes of eight instructions a shown in the following table: Opcode symbol Instruction description Opcode (binary) 1000 AND AND memory cell with AC and writes result in AC. OR 1001 OR memory cell with AC and writes result in AC ADD 1010 SUB 1011 ADD memory cell to AC Subtract memory cell from AC and store result in AC Load 1100 to Load memory cell to AG Store 1101 Store AC to memory cell BR Branch to memory address 1110 1111 BRZ Branch to memory address if zero flag is set What is the opcode [in binary) of the instruction that will be fetched and executed next? After executing the first instruction, the result stored in AC (16-bit binary)'is Give the contents of registers PC, MAR, MBR, and IR in binary after executing the first instruction PC [12-bit binary] = MAR (12-bit binary]= MBR [16-bit binary] = IR (16-bit binary]