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(Answered): The pressure, volume, temperature, and mass of an ideal gas arerelated by the ideal gas equation of ...



The pressure, volume, temperature, and mass of an ideal gas are related by the ideal gas equation of state: PV = MRT M where

The pressure, volume, temperature, and mass of an ideal gas arerelated by the ideal gas equation of state: PV = MRT M where Prepresents pressure (Pascals), V represents volume (cubic meters),m represents mass (grams), T represents temperature (Kelvin), and Mrepresents the molecular mass of the gas (grams/mole). R is theideal gas constant and has a value of 8.31447 Joules/(mole-Kelvin).The temperature decrease a gas experiences during a cooling processdepends on the molecular weight, M, of the gas. Consider thefollowing two gasses: • Oxygen, 02, M = 15.999 grams/mole • CarbonDioxide, CO2, M = 44.01 grams/mole Suppose a mass of 100 grams ofgas at a starting pressure of 500 x 103 Pascals undergoes a coolingprocess at a constant volume of V = 0.15 cubic meters. Heat isremoved until the pressure decreases to 100 x 103 Pascals. Write ascript to compute the temperature values corresponding to 100equally-spaced pressure values in descending order ranging from 500x 103 Pascals to 100 x 103 Pascals for each of the two gasses.Assign the temperature values for oxygen as a row vector to avariable named T02. Assign the temperature values for carbondioxide as a row vector to a variable named TC02. Solve thisproblem using vectorized code (i.e. do not use a loop in yoursolution - points will be lost if you use these.)

The pressure, volume, temperature, and mass of an ideal gas are related by the ideal gas equation of state: PV = MRT M where P represents pressure (Pascals), V represents volume (cubic meters), m represents mass (grams), T represents temperature (Kelvin), and M represents the molecular mass of the gas (grams/mole). R is the ideal gas constant and has a value of 8.31447 Joules/(mole-Kelvin). The temperature decrease a gas experiences during a cooling process depends on the molecular weight, M, of the gas. Consider the following two gasses: • Oxygen, 02, M = 15.999 grams/mole • Carbon Dioxide, CO2, M = 44.01 grams/mole Suppose a mass of 100 grams of gas at a starting pressure of 500 x 103 Pascals undergoes a cooling process at a constant volume of V = 0.15 cubic meters. Heat is removed until the pressure decreases to 100 x 103 Pascals. Write a script to compute the temperature values corresponding to 100 equally-spaced pressure values in descending order ranging from 500 x 103 Pascals to 100 x 103 Pascals for each of the two gasses. Assign the temperature values for oxygen as a row vector to a variable named T02. Assign the temperature values for carbon dioxide as a row vector to a variable named TC02. Solve this problem using vectorized code (i.e. do not use a loop in your solution - points will be lost if you use these.)


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